Watched Videos

Implement the count_views function. It accepts an array of pointers to the Viewer struct, the size of the array, and the character array with the video name. It should return the number of Viewers who have watched a Video with the name video_name.

For example,

Video videos[] = { {.name = "Soccer", .unique_views = 500},
                   {.name = "Basketball", .unique_views = 1000} };
Viewer viewer = {.username = "Dave", .watched_videos = videos,
                 .watched_videos_size = 2};    
Viewer *viewers[] = { &viewer };

calling count_views(viewers, 1, "Soccer") should return 1.

Show starting code

#import <stdio.h>
#import <stdlib.h>

typedef struct Video {
    char *name;
    int unique_views;
} Video;

typedef struct Viewer {
    char *username;
    Video *watched_videos;
    int watched_videos_size;
} Viewer;

int count_views(Viewer **viewers, int viewers_size, char *video_name)
{
    // Waiting to be implemented
    return -1;
}

#ifndef RunTests
int main()
{
    Video videos[] = { {.name = "Soccer", .unique_views = 500},
                       {.name = "Basketball", .unique_views = 1000} };
    Viewer viewer = {.username = "Dave", .watched_videos = videos,
                     .watched_videos_size = 2};
    
    Viewer *viewers[] = { &viewer };
    printf("%d", count_views(viewers, 1, "Soccer")); /* should print 1 */
}
#endif

Example case: Wrong answer
Some people did not see the video: Wrong answer
Various people and videos: Wrong answer
Strings are dynamically allocated: Wrong answer

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